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25x^2-44x-12=0
a = 25; b = -44; c = -12;
Δ = b2-4ac
Δ = -442-4·25·(-12)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-56}{2*25}=\frac{-12}{50} =-6/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+56}{2*25}=\frac{100}{50} =2 $
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